an electric geyser has the rating 2000w-220v marked on it .what should be the minimum current rating (in whole number) of the fuse_wire to be used?
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acc. to me the ans could be
p = v^2/r
R=V^2/P
=220into 220÷2000
=24.2 ohm
now
I=V/R
=220/24.2
= 9.09 ampere
p = v^2/r
R=V^2/P
=220into 220÷2000
=24.2 ohm
now
I=V/R
=220/24.2
= 9.09 ampere
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