An electric geyser has the rating 2000w - 220v marked on it find minimum current rating of fuse used
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we have P = I* V where I is the current and V is the voltage
from this equation
I = P/V
=> current = 2000/220 = 9.09 amp
so if we use fuse less than 9 amp the fuse will blow
from this equation
I = P/V
=> current = 2000/220 = 9.09 amp
so if we use fuse less than 9 amp the fuse will blow
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