Physics, asked by malvebhumika, 3 months ago

An electric geyser rated 500 W operates
one hour/day. If the cost of unit is * 3.00, find
the cost of energy to operate it for the month of
August

Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
10

Given

  • Power = 500 W
  • Time = 1 Hour/day
  • Cost = 3 per unit

To Find

  • Current Bill for the month of August

Solution

E = P × t

Electrical Energy consumed/day :

→ E = P × t

  • Power = 500 W = 500/1000 = 0.5 kW
  • Time = 1 hour

→ E = 0.5 × 1

→ E = 0.5 kWh

Electrical Energy Consumed/August :

  • The month of August has 31 days

→ Eₙₑₜ = 0.5 × 31

→ Eₙₑₜ = 15.5 kWh

━━━━━━━━━━━━━━━━━━

Current Bill :

→ Current Bill = Cost per unit × Energy Consumed

→ Current Bill = 3 × 15.5

→ Current Bill = ₹46.5

Answered by Anonymous
2

Answer:

Given :-

  • Cost per unit = ₹3.00
  • Power = 500 W
  • Time = 1 hour per day

To Find :-

Electricity bill

Solution :-

Firstly lets find total energy consumed per day

E = P × T

Power = 500/1000 = 0.5 W

 \sf \: energy \: consumed = 0.5 \times 1

 \sf \: energy \: consumed \:  = 0.5 \: kWh

Now,

Let's find total cost of 31 days

 \sf \: total \: cost = 0.5 \times 31

 \sf \: total \: cost = 15.5 kWh

Now,

Let's find total bill

 \sf \: total \:  \: bill \:  = 15.5 \times 31

 \sf \: total \:  \: bill \:  =₹46.5

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