Question

An electric geyser rated 600 W is operated for 10
hour/day and an electric refrigerator rated 350 W is
operated for 12 hour/day. What is the cost of the
energy to operate them in the month of june at
the rate of Rs. 5.00 per kWh?
​

Answer 1

Explanation:

Given,

Power = P = 400W = 400/1000 kW = 0.4 kW

Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h

Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh

Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR.

Answer 2

Answer:

Given,

Power = P = 400W = 400/1000 kW = 0.4 kW

Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h

Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh

Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR

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