Question

An electric heater connected to a 220V line has two resistance coils of 22Ω each. Calculate

the current if these coils are used a) separately b) in series c) in parallel.​

Answer 1

Explanation:

Given V=220 V

RA = RB = 24 ohm

(a) Current drawn when only coil A is used:

I = V/RA = 220/24

  =9.16 amps

(b) Current drawn when coils A and B are used in series:

Total resistance, R = RA + RB = 24 + 24 = 48 ohms

 I = V/R = 220/48

  = 4.58 amps

(c) Current drawn when coils A and B are used in parallel:

Total resistance, 1/R = 1/RA + 1/RB = 1/24 + 1/24 = 2/24 = 1/12

R=12 ohms

I = V/R = 220/12

  =18.33 ampere..

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