Question

An electric heater connected to a 220vline has twho resistance coil of 22 each. Calculate the current if these coils are used separatly

Answer 1

I=V/R

I= 220/24

I= 9.16 A

B) THEY ARE CONNECTED IN SERIES HENCE THEIR TOTAL RESISTENCE WILL BE:- 24+24= 48

I = V/R

I = 220/48

I = 4.583 A

C) THEY ARE CONNECTED IN PARALLEL HENCE THEIR TOTAL RESISTANCE WILL BE:- 1/24 + 1/24 = 1/12 = 12

V= IR

I = V/R

I = 220/12

I = 18.33 A

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