An electric heater draws 3.5 a from a 110 v source .the resistance of the heating element is approximately
Answers
Answered by
32
given,
current I =3.5 ampere
potential different V =110v
let the resistance =R
using ohm's law,
V=IR
or,R=V/I
R=110/3.5
R=31.42 ohm.
hence the resistance is approximately 31.42ohm.
current I =3.5 ampere
potential different V =110v
let the resistance =R
using ohm's law,
V=IR
or,R=V/I
R=110/3.5
R=31.42 ohm.
hence the resistance is approximately 31.42ohm.
Answered by
2
Given :
Current (I) = 3.5 A
Potential Difference (V) = 110 V
To Find :
Resistance of the heating element
Solution :
According to Ohm's Law, at constant temperature and other physical conditions, the current flowing through the conductor is directly proportional to the potential difference across the ends of the conductor. So,
Potential Difference (V) = Current (I) × Resistance (R)
So,
Resistance (R) =
=
= 31.43 ohm
Therefore, the resistance of the heating element is found to be 31.43 ohm
Similar questions