Physics, asked by yasho1243, 1 year ago

An electric heater draws 3.5 a from a 110 v source .the resistance of the heating element is approximately

Answers

Answered by mawbleiwelldone
32
given,
current I =3.5 ampere
potential different V =110v
let the resistance =R
using ohm's law,
V=IR
or,R=V/I
R=110/3.5
R=31.42 ohm.
hence the resistance is approximately 31.42ohm.
Answered by AnkitaSahni
2

Given :

Current (I) = 3.5 A

Potential Difference (V) = 110 V

To Find :

Resistance of the heating element

Solution :

According to Ohm's Law, at constant temperature and other physical conditions, the current flowing through the conductor is directly proportional to the potential difference across the ends of the conductor. So,

Potential Difference (V) = Current (I) × Resistance (R)

So,

Resistance (R) = \frac{V}{I}

                        = \frac{110}{3.5}

                        = 31.43 ohm

Therefore, the resistance of the heating element is found to be 31.43 ohm

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