Question

An electric heater having resistance equal to 5Ω is connected to electric source. If it

produces 180 J of heat in one second, find the potential difference across the electric

heater.​

Answer 1

Solution :

⏭ Given:

✏ Resistance of heater = 5Ω

✏ Heat produced by heater = 180J

✏ Time interval = 1s

⏭ To Find:

✏ Potential difference across heater.

⏭ Formula:

✏ Formula of heat energy produced by electrical instrument in terms of potential difference, resistance and time is given by

$\bigstar \: \underline{ \boxed{ \bold{ \sf{ \large{ \red{H = \dfrac{ {V}^{2} }{R} \times t}}}}}} \: \bigstar$

⏭ Terms indication:

• H denotes heat energy
• V denotes p.d.
• R denotes resistance
• t denotes time interval

⏭ Calculation:

$\leadsto \sf \: 180 = \dfrac{ {V}^{2} }{5} \times 1 \\ \\ \leadsto \sf \: {V}^{2} = 180 \times 5 \\ \\ \leadsto \sf \: {V}^{2} = 900 \\ \\ \leadsto \sf \: V = \sqrt{900} \\ \\ \leadsto \: \boxed{ \sf{ \purple{V = 30 \: Volt}}} \: \gray{ \bigstar}$

Answer 2

Answer:

Potential difference across the electric heater is 30volt.