Question

An electric heater having resistance equal to 5Ω is connected to electric source. If it

produces 180 J of heat in one second, find the potential difference across the electric

heater.​

Answer 1

R=5ohm

h=180j

t=1s

h=(v²/R ) × t

v²=(180×5)/1

v²=900

v=√900

v=30v