Question

An electric heater having resistance equal to 5Ω is connected to electric source. If it produces 180 J of heat in one second, find the potential difference across the electric heater​

Answer 1

180=v²/5

v²=180*5

v²=900

v=√900

v=30 volt ans

Answer 2

Answer:

ans

Explanation:

energy = (potentia difference)^2 / rasistance

180j=(v)^2/5

(v)^2=180×5

v=√900

v=30 volt