An electric heater in designed to specade in main with a power output of woow. When connected to Aber Joncie, Power output
Answers
Answer:
Power of heater, P=1000W and potential difference is V=100V.
Thus, resistance of heater is: R
1
=
P
V
2
=
1000
100
2
=10Ω
Now it is connected in series to parallel combination of R and 10Ω resistor.
Thus the equivalent resistance of the whole circuit is R
2
=10+R∣∣10=10+
10+R
10R
=
10+R
100+20R
Now the power,
R
2
V
2
=P
′
=625
R
2
=
625
100
2
=16
10+R
100+20R
=16
100+20R=160+16R
4R=60⇒R=15Ω
Explanation:
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Answer:
When the heater is connected to the supply its initial current will be slightly higher than its steady value but due to heating effect of the current the temperature will rise. This causes an increase in resistance and a slight decrease in current to steady current.
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