An electric heater is rated 1500 watt - 250 volt. Find out:-a)its resistance (b) flow of current through it at 250 volt (c) released heat energy in 10 minutes.
Answers
Explanation:
a) We know that power=voltage²/resistance
P = V²/R
1500 = 62500/R
R = 625/15 = 125/3 = 41.67 ohms.
b) V = IR
I = V/R
I = 250×3/125
I = 6 ampere.
c) Power = Energy/ Time
E = Power×Time
E = 1500 × 10×60
E = 90000 joules.
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Given : An electric heater is rated 1500 watt - 250 volt.
To find : (a) resistance of electric heater
(b) flow of current through it at 250 volts.
(c) released heat energy in 10 minutes.
solution : (a) resistance, R = V²/P
where V is voltage and P is power of electric heater.
here V = 250 volts , P = 1500 watt
so, R = (250)²/1500 = 625/15 = 41.67 Ω
Therefore the resistance of electric heater is 41.67 Ω.
(b) using formula, P = Vi
⇒i = P/V = 1500/250 = 6A
current flows through it is 6A.
(c) heat energy released in 10 minutes, E = P × t
= 1500 watt × 10 × 60 sec
= 1500 × 600
= 90 × 10⁴ J
= 900 kJ