Question

. An electric heater is rated 500 W, 200 V. If the heater is operated for 1 hour, calculate the
energy consumed (i) in kWh and (ii) in J.​

Answer 1

Answer:-

E = 1,800,000J

Or, 1800 KJ

Given :-

p = 500 w

v = 200v

t = 1 h

3600 s

To find :-

The energy consumed :-

SOLUTION:-

The energy consumed by electric heater is given by :-

$\huge \boxed {E = p \times t}$

Put the given value,

→$E = 500 \times 3600$

→$E = 1,800,000 j$

To convert it in to kJ

To convert it in to kJ1 KJ = 1000 J

→$E = \dfrac{1,800,000}{1000}$

→$E = 1800 kJ$

hence,

The energy consumed is 1800 kJ.

Answer 2

Explanation:

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