an electric heater of 1000W is used for two hours in a day. what is the cost of using it for a month of 28 days,if one unit costs 3.00 rupees?
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Answered by
129
energy consumed by heater of 1000W for 2h in one day=1000/1000×2 =2units
number of units=W×h×day/1000
energy consumed by heater in 28 day
2×28=56units
cost of 1unit =RS 3
cost of 56unit=3×56=RS 168
number of units=W×h×day/1000
energy consumed by heater in 28 day
2×28=56units
cost of 1unit =RS 3
cost of 56unit=3×56=RS 168
Answered by
27
Rs. 168 would be the cost for using it for a month of 28days.
Explanation:
Power = 1000W or 1 KW
As we know,
1 unit of electricity = 1KWh
To calculate the energy consumed per day = P * T
= 1KW * 2h
= 2KWh
Total energy consumed in 28days = 2 * 28
= 56KWH
Cost of 1 KWh(1 unit) = Rs. 3
∵ Total cost of 56KWh of energy = 56 * 3
= Rs. 168
Learn more: cost of using energy
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