an electric heater of 2000 watt and an electric iron of 1000 watt run simultaneously on 220 volt and 5A cable. what result do you expect?
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Answer:
Power =P=VI⟹1000=250I⟹I=
250
1000
=4A
∴(i) Electric current flowing through heater=I=4A
∴(ii) Resistance of heated wire R=
I
V
=
4
250
=62.5Ω
∴(iii) Thermal energy produced per minute by heater=E
T
=P×1min=1000×60sec=60000J
∴(iv) Electrical energy spent in kilowatt-hour by heater in 2 hours=
1000
P
KW×2hour=2KW-hour
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