Question

An electric heater of power 1000W has a resistance of 10 ohm. calculate the magnitude of ​

Answer 1

Correct Question :)

An electric heater of power 1000W has a resistance of 10 ohm. calculate the magnitude of current

Solution :)

Given ,

Electric power (P) = 1000 watt

Resistance (R) = 10 ohm

We know that ,

The electric power in terms of current and resistance is given by

$\large \mathtt{\fbox{Electric \: \: power = {(I) }^{2} × R}}$

Where ,

I = Current

R = Resistance

Substitute the known values , we get

1000 = (I)² × 10

(I)² = 1000/10

(I)² = 100

(I) = 10 amp

Hence , the magnitude current is 10 amp

Answer 2

Answer:

Explanation:

POWER,P = 1000 W

RESISTANCE,R = 10 OHMS.

VOLTAGE,V = ?      [ ACCORDING TO THE GIVEN INFORMATION VOLTAGE  COULD BE DETERMINED]

POWER = V²/R

1000 = V²/10

V² = 10000

V = 100 VOLT

CURRENT , I = V/R

CURRENT , I =100/10

I = 10 A .

HOPE THIS HELPS.