Question

An electric heater of power 1470 watt has a resistance of 30 ohm calculate the magnitude of the current and the potential difference at its end .

Answer 1

using the formula
P=I^2×R
1470=I^2×30
I^2=1470÷30
I^2=49
I=√49
hence I = 7 amperes
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Answer 2

P = I² R

1470 / 30 = I²

I = √49 A

I = 7 A

P = I V 

1470 / 7  =  V 

V = 210 volt