An electric heater of power 2500 W is used for 50 s. Find the energy supplied by the heater.
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Explanation:
Hence the heating effect produced by an electric current, I through a conductor of resistance, R for a time, t is given by H = I2Rt. This equation is called the Joule's equation of electrical heating. b)The resistance of the filament used in the bulb.
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Answered by
1
Explanation:
Power=2500w=1500/1000=2.5kw
time=50seconds
Energy=power*time
=1.5*50
=75kws
Energy used by the heater in 50 second=75kws
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