Question

An electric heater of power 2500 W is used for 50 s. Find the energy supplied by the heater.

Answer 1

Explanation:

Hence the heating effect produced by an electric current, I through a conductor of resistance, R for a time, t is given by H = I2Rt. This equation is called the Joule's equation of electrical heating. b)The resistance of the filament used in the bulb.

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Answer 2

Explanation:

Power=2500w=1500/1000=2.5kw

time=50seconds

Energy=power*time

=1.5*50

=75kws

Energy used by the heater in 50 second=75kws