Physics, asked by mundasingh63, 7 months ago

An electric heater of power 3 kW is used for 10
How much energy does it consume ? Express yo
answer in (i) kWh, (ii) joule.​

Answers

Answered by gangahrushikesh2008
6

Answer:

3.6 million Joules

One kilowatt-hour is equivalent to the energy of 1,000 joules used for 3,600 seconds or 3.6 million Joules. In equation form: 1 kWh = 3.6 million J.

Estimate hourly running cost

SO, a portable heater with an input power of 2000 watts, or 2kW, will cost roughly 56 cents for every hour it is on. You can then multiply this by the number of hours per day you use the appliance to calculate a daily running cost.

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Answered by TheUntrustworthy
2

Power = 3 kW = 3000 W

Time = 10 h = 36000 s

 { \red{ \bf{  P=E/T }}}

 { \red{ \bf{ E=P×T  }}}

E=3000×36000

E = 108000000J

 { \red{ \bf{ In\: Joule \: = 1.08×10⁸J }}}

1kWh = 3600000J

 { \red{ \bf{  So, }}}

108000000/3600000

 { \red{ \bf{  In \: kWh \: =30kWh \: Ans }}}

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