Physics, asked by anku3683, 8 months ago

An electric heater of power 3kW is used for 10 hr. How much energy does it consume? Express your answer in (i) kWh (ii) joule please give correct answer​

Answers

Answered by Keerthana16727
0

Answer:

1. 30 kWh

2.30 joules

Explanation:

Energy=power*time

=3*10

=30

Answered by TheUntrustworthy
21

Power = 3 kW = 3000 W

Time = 10 h = 36000 s

 { \orange{ \bf{  P=E/T }}}

 { \orange{ \bf{ E=P×T  }}}

E=3000×36000

E = 108000000J

 { \orange{ \bf{ In\: Joule \: = 1.08×10⁸J }}}

1kWh = 3600000J

 { \orange{ \bf{  So, }}}

108000000/3600000

 { \orange{ \bf{  In \: kWh \: =30kWh \: Ans }}}

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