An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10 ℃ to 15℃ in 100 s.
Calculate :
(i)the specific heat capacity of the liquid.
(ii)the heat capacity of 4.0 kg of liquid.
Answers
An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10 ℃ to 15℃ in 100 s.
Calculate :
(i)the specific heat capacity of the liquid.
(ii)the heat capacity of 4.0 kg of liquid.
Power of heater P = 600 W
Mass of liquid m = 4.0 kg
Change in temperature of liquid = (15 - 10)℃ = 5 ℃ (or 5 K)
Time taken to raise its temperature = 100s
Heat energy required to heat the liquid =
ΔQ = mcΔT
and,
ΔQ = P × t
c = ΔQ/mΔT = 60000/4 × 5 = 3000Jkg^-1K^-1
Heat capacity= c x m
Heat capacity= 4 x 3000JKg^-1K^-1 = 1.2 x 104 J/K
Answer:
The degree symbol or degree sign, °, is a typographical symbol that is used, among other things, to represent degrees of arc, hours, degrees of temperature or alcohol proof. The symbol consists of a small superscript circle
Explanation: