an electric heater of power ratings 2000W, 220V is to obtained in an electric circuit of fuse rating of 5A. what is likely when the heater is switched on Explain
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Power(P)=2000w
Potential difference(V)=220v
we know that,
P=VI
=> I=P/V
I=2000/220
I=9.09ampere
So, current required is 9.09 ampere
But the circuit has current of 5 ampere
So, when we will switch on the heater, a large amount of heat will be released. The fuse wire will melt due to this excessive current and the circuit will be opened. Thus, no current will flow through the circuit. So, the heater will stop
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