Question

An electric heater of resistance 500 ohm is connected to a main supply for 30 minutes.
If 5A current flows through the filament of the heater, calculate the heat energy
produced in the heater.

Answer 1

Answer:

We know that the formula of heat is given by: Heat, H = I2 Rt

Where,

t = 30 min = 30×60 sec = 1800sec

I = 5A

R = 500ohm

H=(5)^2*500*1800

H=25*500*1800

H=225*10^5j

Answer 2

Answer:

22500 KJ

Step-by-step explanation:

I = 5A

R = 500 Ω

T = 30 MIN = 1800 SECONDS

H = I²RT

H = 5²× 500 × 1800

H = 22500 KJ

THE HEAT ENERGY PRODUCED IS 22500 KJ

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