an electric heater of resistance 500 ohms is connected to a main supply for 30 minutes. if 15A current flows through the filament of heater, then calculate the heat energy produced in the heater
Answers
Answered by
82
Heat energy = H= I^2Rt
= (15)^2×500×30×60. •1min=60sec
H=202500000J
H=202.5MJ. •1MJ=10^6J
= (15)^2×500×30×60. •1min=60sec
H=202500000J
H=202.5MJ. •1MJ=10^6J
Answered by
115
Given:
Resistance= R= 500 OHMS
Time= t= 30 min=30*60 Seconds
Current= I= 15A
Heat energy produced=?
Amount of heat energy produced will be given by Joule' s law of heating
H= V*I*t
V= IR ( by OHMS law)
= 15* 500
= 7500 VOLTS.
H=7500*15*30*60
=20,250,0000 Joules
= 2025 x 10^5 Joules.
Therefore, the heat energy produced in the heater is 2025 x 10^5 Joules
Resistance= R= 500 OHMS
Time= t= 30 min=30*60 Seconds
Current= I= 15A
Heat energy produced=?
Amount of heat energy produced will be given by Joule' s law of heating
H= V*I*t
V= IR ( by OHMS law)
= 15* 500
= 7500 VOLTS.
H=7500*15*30*60
=20,250,0000 Joules
= 2025 x 10^5 Joules.
Therefore, the heat energy produced in the heater is 2025 x 10^5 Joules
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