Question

An electric heater of resistance 6 ohm takes a current of 13 A from the mains supply line. Calculate the rate at which heat is developed in the heater? ​

Answer 1

Answer:

Rate of generating heat is equal to the power used by the heater.

By Joule's Law of heating,

P=I^2R

13^2×6 = 1014

Hence, rate of generation of heat is 1014W

please mark as brailiest answer

Answer 2

Explanation:

Given parameters

The resistance of the electric heater (R) = 6 Ω

Current drawn (I) = 13 A

Time = 2 hrs

T = 120 min x 60

Time (T) = 7200 secs

The rate of heat produced by the device in terms of power is expressed as

P= I2R

P = 13 x 13 x 6

P = 1014 watt

Answer

P= 1014 watt