Question

An electric heater of resistance 8 Ω draws 15 A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.
ans fast!

Answer 1

R = 8 
I = 15 
P = I^2R 
   = 15*15*8
    = 1800 w

Answer 2

The rate at which heat is developed in the heater is 1800 W.

Explanation:

Given the resistance of the heater, $R = 8 \Omega$

Current drawn, i = 15 A.

The expression of the power is given as,

$P=i^2R$

Substitute the given values, we get

$P=(15A)^2\times8\Omega$

P = 1800 W.

Hence, the rate at which heat is developed in the heater is 1800 W.

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