An electric heater of resistance 8 Ω draws 15 A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.
Answers
Answered by
17
R = 8 ohm
I = 15A
t = 2 hrs
rate of heat developed = (I^2Rt)/t
=I^2R
= (15)^2 × 8
=225 × 8
= 1800W
I = 15A
t = 2 hrs
rate of heat developed = (I^2Rt)/t
=I^2R
= (15)^2 × 8
=225 × 8
= 1800W
Answered by
4
As per the given details, we can take the resistance of electrical heater as R and current as I.
The given time duration t is 2 hours.
The rate of heat is calculated below.
R = 8 ohm
I = 15A
t = 2 hrs
The rate of heat developed = (I^2Rt)/t
=I^2R
= (15)^2 × 8
= 1800W
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