an electric heater of resistance 8 draws 15 current from the service main 2hrs calculate the rate at which heat is develope in the heater
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Given that Resistance of the electric heater (R) = 8 Ω
Current drawn (I) = 15 A
We know that P = I ² R
= 15×15×8
= 1800w or J/s
Heat is produced by the heater at the rate of 1800 J/s.
Current drawn (I) = 15 A
We know that P = I ² R
= 15×15×8
= 1800w or J/s
Heat is produced by the heater at the rate of 1800 J/s.
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