Question

An electric heater of resistance 8Ω draws 15A from the service mains for 2 hours. Calculate the rate at which heat is developed in the heater.​

Answer 1

Answer:

Given parameters

The resistance of the electric heater (R) = 8 Ω

Current drawn (I) = 15 A

Time = 2 hrs

T = 120 min x 60

Time (T) = 7200 secs

The rate of heat produced by the device in terms of power is expressed as

P= I2R

P = 15 x 15 x 8

P = 1800 watt

Answer

P= 1800 watt

Explanation:

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Answer 2

★ Required AnswEr:

• The rate at which heat is developed in the heater = 1800 Watts

★ Given Information:

• An electric heater of resistance 8Ω draws 15A from the service mains for 2 hours.

★ Need To Find Out:

• Calculate the rate at which heat is developed in the heater.

★ Required Solution:

• Current = 15A
• Resistance = 8Ω
• Time = 2 hours

★ Formula Used Here:

• Electric Power = Current² × Resistances

★ Putting the values:

=> Electric Power = (15)² × 8

=> Electric Power = (15 × 15) × 8

=> Electric Power = 225 × 8

=> Electric Power = 1800 Watts

★ ThereFore:

• The rate at which heat is developed in the heater is 1800 Watts.