An electric heater of resistance 8 ohm draws 15 A from the service mains 2 hours . Calculate the heat which is developed
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Given that - R = 8 ohm
I = 15 A
T = 2 hrs = 2 x 60 x 60 = 7200 s
by the formula of heat energy we know that ,
H = I2 R T
H = I X I X R X T
H = 15 x 15 x 8 x 7200 = 12960000 J = 12960 KJ
hoped so u got the ans....
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