Question

An electric heater of resistance 8 ohm draws 15 A from the service mains 2 hours . Calculate the heat which is developed​

Answer 1

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We know that,

Heat produced = H = I²Rt

Given that,

I = 15A

R = 8Ω

t = 2hr = 2*60*60 = 7200s

H = I²Rt

H = 15² * 8 * 7200

H = 1,29,60,000J

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Answer 2

Answer:

1.296 × 10⁴ k J

Explanation:

Given :

Current I = 15 A

Resistance R = 8 Ω

Time t = 2 hr = 2 × 60 × 60 = 72 × 10² sec

We have to find Heat :

We know :

H = I² R t

Putting values here we get :

= > H = 15² × 8 × 72 × 10² J

= > H = 15 × 120 × 72 × 10² J

= > H = 15 × 72 × 12 k J

= > H = 12960 k J

= > H = 1.296 × 10⁴ k J

Therefore , heat developed in electric heater is 1.296 × 10⁴ k J