Question

An electric heater of resistance 8 ohm draws 15 A from the service mains in 2 hours. Calculate the heat developed in the heater.

Answer 1

Answer:

12960kj

Explanation:

H = I^2 *R *T

I= 15A

R = 8OHM

T = 2HOURS = 3600*2 SECONDS

HENCE ,  

H = 15 * 15 * 8 *2 *3600

  = 3600 * 3600

 = 12960000J

 = 1.296 * 10^ 4  kj (kilojule...1kj = 1000j)

Answer 2

Explanation:

Power P=VI=I²R

R=8Ω

I=15A

∴P=(15)².8=1800 watt

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