Question

an electric heater of resistance 8 ohm draws 15 A from the service mains 2 hours calculate the rate at which it is developed in the heater​

Answer 1

Answer:

Given parameters

The resistance of the electric heater (R) = 8 Ω

Current drawn (I) = 15 A

Time = 2 hrs

T = 120 min x 60

Time (T) = 7200 secs

The rate of heat produced by the device in terms of power is expressed as

P= I2R

P = 15 x 15 x 8

P = 1800 watt

Answer

P= 1800 watt

Explanation:

Answer 2

Answer:

P= I^2 × R

P= 15^2 × 8

P= 225×8 = 1800W