Question

An electric heater of resistance 8 ohm draws 15 A from the service mains in 2 hrs. Calculate the rate at which heat is developed in the heater.

Answer 1

Answer:

$\huge{ \pink{Power P=VI={I }^{2} R}}$

$\red \R= \red{8Ω }$

$\huge{ \blue{I=15A}}$

$\huge{ \color{cyan}∴P={(15) }^{2} .8=1800watt }$

Explanation:

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Answer 2

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Given parameters

The resistance of the electric heater (R) = 8 Ω

Current drawn (I) = 15 A

Time = 2 hrs

T = 120 min x 60

Time (T) = 7200 secs

The rate of heat produced by the device in terms of power is expressed as

P= I2R

P = 15 x 15 x 8

P = 1800 watt