English, asked by Mbappe007, 5 hours ago

An electric heater of resistance 8 ohm draws 15 A from the service mains in 2 hrs. Calculate the rate at which heat is developed in the heater.

Answers

Answered by jeevankishorbabu9985
3

Answer:

 \huge{ \pink{Power P=VI={I }^{2} R}}

 \red \R= \red{8Ω }

 \huge{ \blue{I=15A}}

 \huge{ \color{cyan}∴P={(15) }^{2} .8=1800watt }

Explanation:

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Answered by Limafahar
3

♧︎︎︎ᴀɴsᴡᴇʀ♧︎︎︎

Given parameters

The resistance of the electric heater (R) = 8 Ω

Current drawn (I) = 15 A

Time = 2 hrs

T = 120 min x 60

Time (T) = 7200 secs

The rate of heat produced by the device in terms of power is expressed as

P= I2R

P = 15 x 15 x 8

P = 1800 watt

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