Question

an electric heater of resistance 8 ohm draws 15 ampere from service means for 2 hour calculate the rate at which heat is developed in the heater

Answer 1

Hello buddy

Here's your answer

Hope you find this useful

please mark it as the brainliest

Answer 2

Answer:

The rate of the which the heat developed is 1800watt in the heater.

Explanation:

Given that the resistance, $R=8$Ω

The current flows $I=15A$,

The time heater working $t=2hr$,

We know, Power $P=VR$

From Ohm's law:   $V=IR$

Then Power becomes $P=I^{2}R$

Put the values in above equation:

Power,  $P=(15)^{2}(8)$

           $P=1800A$Ω⁻¹

          $P=1800Js^{-1}=1800watt$

Therefore rate will be equal to 1800watt.