Question

An electric heater of resistance 8 ohm draws 15A
current for 2 hours. Calculate the heat developed in
the resistor.​

Answer 1

Answer:-

• Resistance=R=8ohm
• Current=I=15A
• Time=t=2hours
• Heat=H=?

We know that

$\boxed{\sf H=I^2Rt}$

$\\ \tt\longmapsto 15^2\times 8\times 2$

$\\ \tt\longmapsto 225\times 8\times 2$

$\\ \tt\longmapsto 1800\times 2$

$\\ \tt\longmapsto Heat=3600J$

$\\ \tt\longmapsto Heat=3.6KJ$

Note:-

SI unit of Heat is Joules(J)

Answer 2

Answer:

we know that V/A=R

so,

15/8=R

R=1.875

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