Physics, asked by princessdiya9381, 10 months ago

An electric heater of resistance 8 ohm draws 15A form the service mains 2 hours calculate the rate at which heat is developed in the heater

Answers

Answered by Anonymous
3

Answer:

Given R = 8 ohm

I =15 a t = 2 hours

Ww know that

V =iR

V=120 volt

Now p=vi

P=120 *15

=1800

Now heat is 120*2

240 joule

Answered by Anonymous
4

\Huge{\underline{\underline{\blue{\mathfrak{Answer :}}}}}

\large{\underline{\underline{\red{\sf{Given :}}}}}

Resistane (R) = 8 Ω

Electric current (I) = 15 A

Time (T) = 2 h = 2 * 60 * 60 = 7200 s

\rule{200}{2}

\large{\underline{\underline{\pink{\sf{To \: Find :}}}}}

We have to find Power

\rule{200}{2}

\large{\underline{\underline{\orange{\sf{Solution :}}}}}

We know that,

\Huge{\boxed{\gray{\sf{H = I^2 R T}}}}

(Put Values)

H = (15)² * 8 * 7200

H = 225 * 57,600

H = 12,960,000

\large{\boxed{\pink{\sf{H \: = \: 12,960,000 \: J}}}}

\rule{200}{2}

\Huge{\boxed{\purple{\sf{Power = \frac{Heat}{Time}}}}}

Power = 12960000/7200

Power = 1800

\large{\boxed{\pink{\sf{Power \: = \: 1800 \: Js^{-1}}}}}

\rule{200}{2}

Important Formula's :-

  1. V = W/Q
  2. V = IR
  3. I = Q/T
  4. P =VI
  5. P = I²R
  6. P = V²/R
  7. H = I² RT
  8. P = H/T
  9. P = I²R
  10. H = VIT
  11. W = VQ

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