An electric heater of resistance 8 ohm draws 15A from the service mains in 2 hours. Calculate the rate at which heat is developed in the heater.
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- We need to find the rate at which heat is developed in the heater.
- resistance of heater = 8 Ω
- current in heater = 15A
- time = 2 hours = 7200second
▶ we know that ,
- p = VI
By Ohm's law V = IR
So,
- ⚘ p = I²R
where
- p = power
- I = current
- R = Resistance
Now,
Resistance of heater is 8ohm draws 15A current .
➻ p = 15² × 8
➻ p = 225 × 8
➻ p = 1800 w
Hence,
the rate at which heat is developed in the heater is 1800w.
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⚡Power:-
The rate of doing work is known as power.
⚘SI unit of power is watt (w).
- p = VI
- p = I²R
- p = Work done/Time taken
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Anonymous:
Perfect :D
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