Question

An electric heater of resistance 8 ohm draws 15C of charge per second. Suppose it happens for a period of 2 hours calculate the amount of heat energy derived by the heater?

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Answer 1

$\bold{\underline{\underline{\red{Given~ parameters}}}}$

${:⇒\sf\pink{The~ resistance ~of~ the~ electric~ heater~ (R) = 8 Ω}}$

${:⇒}$$\sf\pink{Current~ drawn~ (I) = 15~ A}$

${:⇒}$$\sf\pink{Time = 2~ hrs}$

${:⇒}$$\sf\pink{T = 120 ~min ×60}$

${:⇒}$$\sf\pink{Time~ (T) = 7200 ~secs}$

$\longrightarrow$ The rate of heat produced by the device in terms of power is expressed as

The heat developed in heater can be calculated using the formula

${↪}$$\tt\purple{H = I²RT}$

${↪}$$\tt\purple{H = 15 × 15 × 8 × 7200}$

${↪}$$\tt\purple{H = 12960000}$

${↪}$$\tt\purple{H = 1296 × 10⁴ J}$

Answer 2

Answer:

Given parameters

The~ resistance ~of~ the~ electric~

(R) = 8 Ω}}:⇒The resistance of the electric heater (R)=8Ω

{:⇒}:⇒ {Current~ drawn~ (I) = 15~ A}Current drawn (I)=15 A

{:⇒}:⇒ {Time = 2~ hrs}Time=2 hrs

{:⇒}:⇒ {T = 120 ~min ×60}T=120 min×60

{:⇒}:⇒ {Time~ (T) = 7200 ~secs}Time (T)=7200 secs

⟶ The rate of heat produced by the device in terms of power is expressed as

The heat developed in heater can be calculated using the formula

{↪}↪ {H = I²RT}H=I²RT

{↪}↪ {H = 15 × 15 × 8 × 7200}H=15×15×8×7200

{↪}↪ {H = 12960000}H=12960000

{↪}↪ {H = 1296 × 10⁴ J}H=1296×10⁴J

Explanation:

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