An electric heater of resistance 8 ohm's draw 15 A from the service mains 2 hours . Calculate the rate at which heat is developed in the heater .
Answers
Answered by
6
H = I^2Rt
= (15)^2×8×7200sec.
= 225×8×7200
= 129600000 J
Please mark as the brainliest
= (15)^2×8×7200sec.
= 225×8×7200
= 129600000 J
Please mark as the brainliest
Answered by
2
Hello friend
your answer is ,
Given R=8
I =15
t=2hour
h=?
Now the formula of heat =I²Rt
=15×15×8×2×60×60j
Power =heat /time
15×15×8×2×60×60/2×60*60=1800j
I hope it helps your
your answer is ,
Given R=8
I =15
t=2hour
h=?
Now the formula of heat =I²Rt
=15×15×8×2×60×60j
Power =heat /time
15×15×8×2×60×60/2×60*60=1800j
I hope it helps your
Similar questions