Question

An electric heater of resistance 8 ohm takes a current of 15 A from the main supply line.Calculate the rate at which heat is developed in the heater.

Answer 1

P=VI = I*I*R

P=15*15*8=225*8=1800w

Answer 2

1800 J/s of heat is developed in the heater.

Explanation:

It is given that,

Current in the heater is 15 A

Resistance of the heater is 8 ohms

We need to find the rate at which heat is developed in the heater. The heat developed in an electrical appliance is given by :

$Q=I^2Rt\\\\\dfrac{Q}{t}=I^2 R\\\\\dfrac{Q}{t}=15^2\times 8\\\\\dfrac{Q}{t}=1800\ J/s$

So, 1800 J/s of heat is developed in the heater.

Learn more

Heat produced

https://brainly.in/question/2609758