Question

An electric heater of resistance 8 Q draws 15 A from the service mains 2 hours Calculate the rate at which heat is developed in the heater.​

Answer 1

Answer:R= 8ohm , I=15A

Explanation:we know that rate of doing work is power

p= I^2*R

P=15*15*8

P=1800 J/S

Answer 2

Answer:

above one is the right answer ☺️