Question

An electric heater of resistance 8ohm draws 15 A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater

Answer 1

Answer:

Q=12960000J.

Explanation:

A/Q

R=8ohm, I=15A

and t=2h=2×60×60=7200s,

Q=?

$q = {i }^{2} rt$

$= {15}^{2} \times 8 \times 7200$

=12960000J