Question

An electric heater of resistance 8ohm draws 15A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.

Answer 1

Hey there!

SOLUTION:

We have the following values:

R = 8 Ohm
I = 15 A
T = 2h

NOW, we know that

H = I² Rt

So:
H = 225 x 8 x 2
H = 3600 J ANS
___________

I hope this helps.
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Answer 2

Heat developed in the heater is given by H =

$\huge\sf\red{{I}^{2}Rt}$

Where,

$\large\sf{I=15A}$

$\large\sf{R=8\mho}$

$\large\sf{time,t=2\:hours}$

The rate at which heat is developed is given by

$\large\sf\purple{H=\frac{{I}^{2}Rt}{t}={I}^{2}R}$

$\longrightarrow$$\large\sf\purple{ {(15)}^{2} \times 8}$

$\longrightarrow$$\large\sf\purple{1800J/s}$