An electric heater of resistance 8ohm draws 15A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.
Answers
Answered by
17
r=8Ω
i=15A
t=2h
e(energy)=i²rt
ie: e=8x8x15x2
e= 1920wh
=1.92kwh
i=15A
t=2h
e(energy)=i²rt
ie: e=8x8x15x2
e= 1920wh
=1.92kwh
karneet:
and you made it the brainliest answer?!
Answered by
2
Hope this helps you... ☺
Follow me @gayathrielayidamu.
Attachments:
Similar questions
Biology,
8 months ago
Physics,
8 months ago
Biology,
1 year ago
Environmental Sciences,
1 year ago
Hindi,
1 year ago