An electric heater of resistance 8ohm draws 15A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.
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Answered by
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r=8Ω
i=15A
t=2h
e(energy)=i²rt
ie: e=8x8x15x2
e= 1920wh
=1.92kwh
i=15A
t=2h
e(energy)=i²rt
ie: e=8x8x15x2
e= 1920wh
=1.92kwh
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