An electric heater of resistance 8ohms draws 15A from the service main calculate at what rate is the cost of operating energy developed
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Answer:
1800 watt
Explanation:
According to the given question,
R = resistance = 8 Ohm
I = Current = 15 Amp
P = Power and H = Energy and t = time
And we are asked to find the rate of energy.
We know,
- Energy = Power× time
- Power = Energy/ time
Thus power is rate of energy. We also know,
- P = I^2 × R
putting the given values we get,
- P = 225×8
- P = 1800 watt
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