Physics, asked by suthardeep, 1 year ago

an electric heater of resistance of 8Ω draws 15 A from the service mains 2 hours.calculate the rate at which heat is developed in the heater?

Answers

Answered by Anonymous

3

Hey ...☺

Here's ur ans. ⬇

.____________________________

H=I^2RT
H=15×15×8×2
H=225×16
H=3600J

Rate = 3600 ÷ 2

= 1800 Joule /sec

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