Question

an electric heater of resistance of 8Ω draws 15 A from the service mains 2 hours.calculate the rate at which heat is developed in the heater?

Answer 1

Hey ...☺


Here's ur ans. ⬇


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H=I^2RT
H=15×15×8×2
H=225×16
H=3600J

Rate = 3600 ÷ 2

= 1800 Joule /sec