Question

An electric heater of resistence 8 ohm draws 15a from the service for 2 hours calculate the rate at which heat is developed in the heater

Answer 1

we know the formula that H = I²Rt...so we r provided with I,Rand t so just calculate it..

Answer 2

Explanation:

Given R = 8 ohms, I = 15 amp, t = 1 sec

We know that

H = I2RT

H = 152 x 8 x 1

H = 1800 J/s

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