Question

An electric heater rated 1200w is used for 4 hours daily in month of February 2021,How much energy (Kwh) does it consume?​

Answer 1

Answer:

i hope it will help you

Explanation:

Solution

Given,

Power = 3 kW

Time = 10 hours

(i) Electrical energy = Electrical power

×Time = 3 kW × 10 hours = 30 kWh

(ii) Since 1 KWh =

3.6×10⁶J

Electrical energy =

30×3.6×10⁶=108×10⁶J

Answer 2

Given: power of heater - P = 1200W = 1.2 KW

                                           t = 4 hours

To Find : Energy - E

Solution:

Formula used: E = P × t

                         E = 1.2 × 4

                            = 4.8 Kwh/day

2021 is not divisible by 4 hence it is not a leap year and ∴ it has 28 days.

Total Energy consumed for february month in 2021 = 4.8 × 28

                                                                                     = 134.4 Kwh