an electric heater rated 1500 W. Then the work done by it in an hour
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Answered by
3
Work done = rate × time
Work done = 1500 ×60
Work done = 90000 W/h = 90 KW/h
Work done = 1500 ×60
Work done = 90000 W/h = 90 KW/h
Answered by
8
Hey mate
-->> 1 hour = 3600 s
-->> Power = 1500W = 1500 kg m^2 s^(-3)
=>> Work done = Power * Time
=>> 1500 * 3600 = 5400000 J
》》1 kilojoule = 10^-3 Joule
==》》 5400kJ
==》》Work done by it in an hour = 5400 kJ
-->> 1 hour = 3600 s
-->> Power = 1500W = 1500 kg m^2 s^(-3)
=>> Work done = Power * Time
=>> 1500 * 3600 = 5400000 J
》》1 kilojoule = 10^-3 Joule
==》》 5400kJ
==》》Work done by it in an hour = 5400 kJ
Anonymous:
sorry I can't delete the answer
my small brother copied and pasted by mistake
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